tolong bantu bang plisssssss
Jawaban:
1. x²-x-12= 0
2. x²-5x+1=0
3. x²+6x+4=0
Penjelasan dengan langkah-langkah:
1.
(x-x1)(x-x2)= 0
(x-4)(x-(-3)) =0
(x-4)(x+3)= 0
x²-x-12= 0
2.
x²-(x1+x2)x+x1x2= 0
x²-(5)x+1= 0
x²-5x+1= 0
3.
x1+x2= -b/a= -3/1= -3
x1x2= c/a= 1/1= 1
(x-2x1)(x-2x2)=0
= x²-(2x1+2x2)x+4x1x2 =0
= x²-(2(x1+x2))x+4x1x2= 0
= x²-2(-3)x+4(1)=0
= x²+6x+4=0
[answer.2.content]
